문제 링크
요약
- Recursion 으로 풀면 된다.
최종
결과
- Recursion 으로 풀면 된다. 난이도가 hard 인것 치고 쉬운 문제.
#define MIN_INT (0x80000000)
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
int traverse(TreeNode *cur, int &global_max) {
int cur_max = cur->val;
int l_max = cur->val;
int r_max = cur->val;
int m_max;
if (cur->left) {
l_max += traverse(cur->left, global_max);
cur_max = max(cur_max, l_max);
}
if (cur->right) {
r_max += traverse(cur->right, global_max);
cur_max = max(cur_max, r_max);
}
if (cur->left && cur->right) {
global_max = max(global_max, l_max + r_max - cur->val);
}
global_max = max(global_max, cur_max);
return cur_max;
}
public:
int maxPathSum(TreeNode* root) {
int ret = MIN_INT;
traverse(root, ret);
return ret;
}
};